Java基础之任意整数转换成对应的2、8、16进制数

class SearchDemo{
	public static void main(String[] args){
		toHex(0);
	}
	//十进制-->十六进制
	public static void toHex(int num){
		trans(num,15,4);
	}
	//十进制-->二进制
	public static void toBinary(int num){
		trans(num,1,1);
	}
	//十进制-->八进制
	public static void toOctal(int num){
		trans(num,7,3);
	}
	//任意一个十进制转换成二进制、八进制、十六进制
	public static void trans(int num,int base,int offset){
		if (num==0) {
			System.out.println("0");
			return;
		}
		char[] chs = {'0','1','2','3','4','5','6','7','8','9','A','B','C','D','E','F'};
		char[] arr = new char[32];
		int pos = arr.length;
		while(num!=0){
			int temp = num & base;
			arr[--pos] = chs[temp];
			num = num >>> offset;
		}
		for (int x=pos;x<arr.length;x++){
			System.out.print(arr[x]);
		}
		System.out.println();
	}
}